Question

Calculati:
(x2-3x+2)3+(2x2+x-3)3=(3x2-2x-1)3

Answer 1

$( x^{2} -3x+2)3+(2*2+x-3)3=(3*2-2x-1)3$
<=> [tex]3x^{2}-9x+6+12+3x-9=18-6x-3 [/tex]
<=> $3 x^{2} -6x+18-9=18-3-6x$
<=> $3 x^{2} -6=0$
<=> $x^{2} =2$ => x₁=$\sqrt{2}$
                                            x₂=-$\sqrt{2}$