Matematică, întrebare adresată de ioniely, 9 ani în urmă

Calculati :
x²-4; 25-x²; 4x²-1; 1-9x²; 16x²-25; 9-4x²; 25a²-b²; 9/25t²-1; 25/36x²-9/16y²; 144x²-9y²; 4x²y²-z²; -49u²+121v²; x²y²-z²; -1+a²b²c²; -y²+169z²; 100a²-9b; 256m²-169n²; -289t²+625p²; 1/4-x²; 0,01a²-1,69b²; x²y²-0,(4); -4,41x²+y²; a²-2; 5-b²; 2x²-3; a²-3b²; 7x²-y²; 2x²-9y²; a⁴-81; 1-x⁴; x⁴-b⁴; 16x⁴-y⁴; 81x⁴-16y⁴; x⁶-y⁴; x⁴-9; 4-a⁴; 25x⁴-9y⁴; 4z⁴-1; x²y⁴-36;
x⁶-2y⁴;


Georgiana987543: ajuuutooooor

Răspunsuri la întrebare

Răspuns de renatemambouko
4

x²-4=(x-2)(x+2)

25-x²=(5-x)(5+x)

4x²-1=(2x-1)(2x+1)

1-9x²=(1-3x)(1+3x)

 16x²-25=(4x-5)(4x+5)

 9-4x²=(3-2x)(3+2x)

 25a²-b²=(5a-b)(5a+b)

 9/25t²-1=(3/5t-1)(3/5t+1)

 25/36x²-9/16y²=(5/9x-3/4y)(5/9x+3/4y)

 144x²-9y²=(12x-3y)(12x+3y)=9(4x-y)(4x+y)

 4x²y²-z²=(2xy-z)(2xy+z)

 -49u²+121v²=121v²-49u²=(11v-7u)(11v+7u)

 x²y²-z²=(xy-z)(xy+z)

 -1+a²b²c²=a²b²c²-1=(abc-1)(abc+1)

 -y²+169z²=169z²-y²=(13z-y)(13z+y)

 100a²-9b²=(10a-3b)(10a+3b)

 256m²-169n²=(16m-13n)(16m+13n)

 -289t²+625p²=625p²-289t²=(25p-17t)(25p+17t)

 1/4-x²=(1/2-x)(1/2+x)

 0,01a²-1,69b²=(0,1a-1,3b)(0,1a+1,3b)

 x²y²-0,(4)=(xy-2/3)(xy-2/3)                        0,4=4/9 =2²/3²

 -4,41x²+y²=y²-4,41x²=(y-2,1x)(y+2,1x)

 a²-2=(a-√2)(a+√2)

 5-b²=(√5-b)(√5+b)

 2x²-3=(x√2-√3)(x√2+√3)

 a²-3b²=(a-b√3)(a+b√3)

 7x²-y²=(x√7-y)(x√7+y)

 2x²-9y²=(x√2-3y)(x√2+3y)

 a⁴-81=(a²-9)(a²+9)=(a-3)(a+3)(a²+9)

 1-x⁴=(1-x²)(1+x²)=(1-x)(1+x)(1+x²)

 x⁴-b⁴= (x²-b²)(x²+b²)=(x-b)(x+b)(x²+b²)

 16x⁴-y⁴=(4x²-y²)(4x²+y²)=(2x-y)(2x+y)(4x²+y²)

 81x⁴-16y⁴=(9x²-4y²)(9x²+4y²)=(3x-2y)(3x+2y)(9x²+4y²)

 x⁶-y⁴=(x³-y²)(x³+y²)

 x⁴-9= (x²-3)(x²+3)=(x-√3)(x+√3)(x²+3)

 4-a⁴=(2-a²)(2+a²)=(√2-a)(√2+a)(2+a²)

 25x⁴-9y⁴=(5x²-3y²)(5x²+3y²)=(x√5-y√3)(x√5+y√3)(5x²+3y²)

 4z⁴-1=(2z²-1)(2z²+1)=(z√2-1)(z√2+1)(2z²+1)

 x²y⁴-36=(xy²-6)(xy²+6)

x⁶-2y⁴=(x³-y²√2)(x³+y²√2)

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