Question

Calculati y=(4^(n+1)+4^n-19∙4^(n-1) )-[(2^n )^2:4]

Answer 1

Răspuns:

+ n = n(n + 1). 2. , b)1+3+5+ ... + (2n − 1) = n2, c) 12 + 22 + 32 + ... + n2 = n(n + 1)(2n + 1). 6. , d) 13 + 23 + 33 + ... + n3 = [n(n + 1). 2. ]2. , e) 1 · 2+2 · 3+3 · 4 +