Question

Calculati z1=3+2i z2=-4+5i calculati z1+z2,z1-z2,z1×z2,z2÷z1

Answer 1

(3+2i)+(-4+5i)=

=3+2i-4+5i

=-1+7i

(3+2i)+(-4+5i)=

=3+2i+4-5i

=7-3i

(3+2i)+(-4+5i)=

=-3×4+3×5i-2i×4+2i×5i

=-12i+15i-8i+10i²

=-12+15i-8i+10×(-1)

=-12+15i-8i-10

=-22+7i

(-4+5i):(3+2i)=-4+5i / 3+2i