Question

Calculatii R pentru Δ ABC daca C=pi supra 3 si AB=8

Answer 1

Teorema sinusurilor : $\frac{a}{sinA}= \frac{b}{sinB}= \frac{c}{sinC}=2R,deci, \frac{AB}{sinC}=2R,sau, \frac{8}{sin \frac{ \pi }{3} }=2R,adica:$$\frac{8}{ \frac{ \sqrt{3} }{2} }=2R,rezulta,R= \frac{8 \sqrt{3} }{3}$