Question

Calculațimasa de calcar de P=80% necesar obținerii prin descompunere a 336kg oxid de
calciu

Answer 1

2CaO→2Ca+O₂
n=m/M
M=40+16=56g/mol
n=336/56=6 kmoli CaO
2 moli CaO...........2 moli Ca
6 kmoli..................6 kmoli
n=m/M    m=n*M=6*40=240 kg Ca pur
p%=m subst pura*100/m subst impura
m subst impura =m subst pura*100/p%=240*100/80=300 kg Calcar