Question

Calculatix^y+y^x pentru:x=8^33:[4^32*2^34+(2^5*2^20)^5:(16*2^23)+(7^5:7^5-1)32*4]
y=[(11-0^11)*(3^3-3^2)+1^2020]*(3^2-2^3)-3^2*2

Answer 1

x=8^33:[4^32*2^34+(2^5*2^20)^5:(16*2^23)+(7^5:7^5-1)32*4]
x=2^99:[2^64*2^34+(2^125:(2^4*2^23)+(1-1)32*4]
x=2^99:(2^98+(2^125:2^27+0)
x=2^99:(2^98+2^98)
x=2^99:(2x2^98)
x=2^99:2^99)
x=1

y=[(11-0^11)*(3^3-3^2)+1^2020]*(3^2-2^3)-3^2*2
y=[11*(27-9)+1]*(9-8)-9*2
y=(11*18+1)*1-18
y=(198+1)*1-18
y=199-18
y=181

x^y+y^x=1^181+181^1=1+181=182