Question

calculato aria trapezului care are baza mare de 15 cm si baza mica 8 cm si inaltimea 6 cm si calculati linia mijlocie a trapezului.​

Answer 1

Răspuns:

Notam baza mica - b

Notam baza mare - B

Notam inaltimea - h

$A_{trapez} =\frac{(b+B)*h}{2}=\frac{(8+15)*6}{2}=\frac{23*6}{2}=\frac{138}{2}= 69 cm^{2}$

$LM=\frac{b+B}{2} =\frac{8+15}{2} \frac{23}{2} =11,5 cm$

꧁Sper ca te-am ajutat!꧂

Answer 2

Răspuns:

A=

$\frac{b - b }{2}$

=>A=

$\frac{15 - 8}{2}$

=> A = l.m × h => A = 11 × 6 => A =66cm²