Question

Calculaza a) 18-(20-6):7-4-4×2; b) [(2+2×3)×2-12]:4+1; c) 10×{81^2:(3^2)^4+2×[(2^2×3)^15+1]}.​

Answer 1

Răspuns:

A)

18-14:7-4-4*2

18-2-4-8

16-4-8=4

B)

[(2+6)*2-12]:4+1

(8*2-12):4+1

(16-12):4+1

4:4+1=2

C)

10{3^8:3^8+2[(4*3)^15+1]}

10[1+2(12^15+1)]

10(1+2*2^15+2)

10(3+2*2^15)

30+20*12^15