Question

Calculează: 10x{81^2:(3^2)4+2x[(2^2x3)^15:(2^29x3^15)+1]}

Answer 1

$\bf 10 \cdot \{81^{2}:(3^{2})^{4} + 2\cdot[(2^{2}\cdot3)^{15}:(2^{29}\cdot3^{15})+1] \} =$

$\bf 10 \cdot \{( 3^{4} )^{2}:(3^{2})^{4} + 2\cdot[(2^{2\cdot15} \cdot3^{15}):(2^{29}\cdot3^{15})+1] \} =</p><p>$

$\bf 10 \cdot \{3^{4 \cdot2}:3^{2 \cdot4} + 2\cdot[(2^{30} \cdot3^{15}):(2^{29}\cdot3^{15})+1] \} =$

$\bf 10 \cdot \{3^{8}:3^{8} + 2\cdot[(2^{30} \cdot3^{15}):(2^{29}\cdot3^{15})+1] \} =</p><p>$

$\bf 10 \cdot [3^{8 - 8} + 2\cdot(2^{30 - 29} \cdot3^{15 - 15}+1]=$

$\bf 10 \cdot [3^{0} + 2\cdot(2^{1} \cdot3^{0}+1)]=$

$\bf 10 \cdot [1+ 2\cdot(2 \cdot1+1)]=$

$\bf 10 \cdot (1+ 2\cdot3)=$

$\bf 10 \cdot (1+ 6)=$

$\bf 10 \cdot 7 =$

$\pink{ \underline{ \: \bf 70 \: }}$