Question

calculeaza:{[(120+2×15)÷75+4]×10la puterea2-40×5}÷80

Answer 1

{[(120+2×15):75+4]×10² -40×5}:80=
{[(120+30):75+4]×100 -200}:80=
[(150:75+4)×100 -200]:80=
[(2+4)×100 -200]:80=
(6x100-200):80=
(600-200):80=
400:80=
=5

Answer 2

{[(120+2×15)÷75+4]×10 ^2 - 40×5}÷80 =
{[( 120+ 30)÷75+4]×(10×10) - 200 } ÷ 80 =
[(150÷75+4) × 100 - 200 ] ÷80
[( 2+4)×100-200] ÷80
(6×100-200)÷80=
(600-200)÷80
400÷80 = 5