Question

calculeaza:2×2×7:[(2×2+2:2)×2-2:2×(2×2-2:2)]​​

Answer 1

Răspuns:

2×2×7:[(2×2+2:2)×2-2:2×(2×2-2:2)]​​=

4·7:[(4+1)·2-2:2·(4-1)]=

28:(5·2-2:2·3)=

28:(10-3)=

28:7=

4

Answer 2

Răspuns: $\color{red}\LARGE \boxed{\bf 4}$

Explicație pas cu pas:

$\large \bf 2\cdot2\cdot7:[(2\cdot2+2:2)\cdot2-2:2\cdot(2\cdot2-2:2)] =$

$\large \bf 2\cdot2\cdot7:[(4+1)\cdot2-2:2\cdot(4-1)] =$

$\large \bf 2\cdot2\cdot7:(5 \cdot2-2:2\cdot 3) =$

$\large \bf 2\cdot2\cdot7:(10-1\cdot 3) =$

$\large \bf 2\cdot2\cdot7:(10-3) =$

$\large \bf 2\cdot2\cdot7:7 =$

$\large \bf 4 \cdot7:7 =$

$\large \bf 4 \cdot 1 =$

$\color{teal}\Large \boxed{\bf 4}$

==pav38==