Question

calculeaza: [(3^5^2 : 3^4^2 : 3^3^2 )^2013 + 2^4^2 : 2^3^2 : 2^2^2]:(-3)=

Ajutor!

Answer 1

= [ (3^25 : 3^16 : 3^9 )^2013 + 2^16 : 2^9 : 2^4 ] ; (-3) = 
   [ ( 3^(25-16-9))^2013 + 2^(16-9-4)] :(-3) =
   [ (3^0)^2013  + 2^3 )] : (-3) =
   [1^2013 + 8] : (-3) = 
   9  : (-3) = 
    - 3 

Answer 2

$\Big[\Big(3^\big{5^\big2} : 3^\big{4^\big2} : 3^\big{3^\big2}\Big)^\big{2013} + 2^\big{4^\big2} : 2^\big{3^\big2} : 2^\big{2^\big2}\Big]\big:(-3) = \\ \\ = \Big[\Big(3^\big{25} : 3^\big{16} : 3^\big{9}\Big)^\big{2013} + 2^\big{16} : 2^\big{9} : 2^\big{4}\Big]\big:(-3) = \\ \\ =\Big[\Big(3^\big{25-16-9}\Big)^\big{2013}+2^\big{16-9-4}\Big]:(-3) = \\ \\ = \Big[\Big(3^\big{0}\Big)^\big{2013}+2^{\big3}\Big]:(-3) = \\ \\ = \Big(1^\big{2013}+2^\big{3}\Big):(-3) = \\ \\ = (1+8):(-3) = \\ \\ = 9:(-3) = \\ \\ = -3$