Question

calculeaza 3 la puterea 45 :(3 la puterea 44+3 la puterea 44+3 la puterea 44)+2 la puterea30:(2 la puterea29+2 la puterea 29)
pls dau coroana!

Answer 1

${3}^{45} \div ( {3}^{44} + {3}^{44} + {3}^{44} ) + {2}^{30} \div ({2}^{29} + {2}^{29} )$

$= {3}^{45} \div (3 \times {3}^{44} ) + {2}^{30} \div (2 \times {2}^{29} )$

$= {3}^{45} \div {3}^{1 + 44} + {2}^{30} \div {2}^{1 + 29}$

$= {3}^{45} \div {3}^{45} + {2}^{30} \div {2}^{30}$

$= 1 + 1$

$= 2$