Question

Calculează:

[(302×15-3.045:15-109×3):100+42×(7×9-63)-0:(1+2+...+100)]:10+7×287=

Vă rog mult, ajutați-mă!!!!

Answer 1

[(4530-203-327):100+42x(63-63)-0:(1+2+3+........+100)]:10+7x287=
[(4327-327):100+42x0-0:(1+2+3+........+100)]:10+7x287=
[(4000:100+0:(1+2+3+.........+100)]:10+7x287=
[(40+0:(1+2+3+...........+100)]:10-7x287=
Nt=(U-P):r+1
Nt=(100-1):1+1
Nt=99:1+1
Nt=99+1
Nt=100
S=[(P+U)xNt]:2
S=[(100+1)xNt]:2
S=(101x100):2
S=10100:2
S=5050
(40+0:50):10+2009=
40:10+2009=
4+2009=2013
Succes !