Question

calculeaza : (32+2×3 la puterea 2):5 la puterea 2+ (2 la puterea 5 totul la 20
Varog ajutati-ma!

Answer 1

$(32+2*3^2):5^2+(2^5)^2^0= \\ \\ (32+2*9):25+2^1^0^0= \\ \\ 50:25+2^1^0^0= \\ \\ 2^1+2^1^0^0$

Answer 2

(32+2×3^ 2):5^ 2+ (2^5) ^20
=(32+2x9):25+ 2 la puterea 5x20
=(32+18):25+ 2^100
= 50:25+2^100
=2+2^100