Question

Calculeaza:{[42×(6-100÷25)×24]-8}÷5= b)12-10÷{1+3×[(57-60÷4×2)÷3+2]÷10}=

Answer 1

a)
{[42×(6-100÷25)×24]-6}÷5=
={[42x(6-4)x24]-6}:5=
=[(42x2x24)-6]:5=
=[(84x24)-6]:5=
=(2916-6):5=
=2910:5=
=582
   
 b)
12-10÷{2+3×[(57-60÷4×2)÷3+1]÷10}=
=12-10:{2+3x[(57-15x2):3+1]:10}=
=12-10:{2+3x[(57-30):3+1]:10}=
=12-10:[2+3x(27:3+1):10]=
=12-10:[2+3x(9+1):10]=
=12-10:(2+3x10:10)=
=12-10:(2+30:10)=
=12-10:(2+3)=
=12-10:5=
=12-2=
=10