Question

Calculeaza:(5pe 6la puterea 2);7pe 3la puterea 2;5pe 4 la puterea 4;(1cu 2pe 3la puterea 3);(7pe 11 la puterea 0);(2cu1pe 2 la puterea 4);11 pe12la puterea 2.

Answer 1

Răspuns:

(5/6)²=25/36

49/9

625/256

1x(2/3)²= introduci = (5/3)²=25/9

7/11 la puterea 0 = 1

5/2 la a 4 =625/16

(11/12)²= 121/144

Explicație pas cu pas:

Answer 2

(5/6)²=25/36

49/9

625/256

1x(2/3)²= introducem = (5/3)²=25/9

7/11 la puterea 0 = 1

5/2 la a 4 =625/16

(11/12)²= 121/144

Sper ca te-am ajutat

Coronița!?