Question

Calculeaza:[(9×6-11+7×3):2^2+9]×5-[(7+29)-6^2] ; 3×{2+740:[77-20+(998-249×4)]}-13×5 ; (32+2×3^2):5^2+(2^5)^28:4^49

Answer 1

[(9×6-11+7×3):2^2+9]×5-[(7+29)-6^2]=
[(54-11+21):4+9]×5-(36-36)=
[(43+21):4+9]×5-0=
(64:4+9)×5=
(16+9)×5=25×5=125

3×{2+740:[77-20+(998-249×4)]}-13×5=
3×{2+740:[77-20+(998-996)]}-65=
3×[2+740:(77-20+2)]-65=
3×(2+740:59)-65=
3×(2+740/59)-65=aducem la acelasi numitor paranteza
3×(118/59+740/59)-65=
3x858/59-65=
2574/59-65= il amplificam pe 65 cu 59
2574/59-3835/59= -1261/59

(32+2×3^2):5^2+(2^5)^28:4^49=
(32+2×9):25+2^140:(2^2)^49=
(32+18):25+2^140:2^98=
50:25+2^42=2+2^42