Question

Calculează 900 ÷[34÷2+(4×25-85÷5)]////9+12÷[42-(40-32÷8)]///100×[386÷2+(8×25-805÷5)]///[(2×3+45÷15)÷9+1]÷2////[(16×3+4×5)÷2+3]×10

Answer 1

900:[34:2+(4×25-85:5)]=

900:[34:2+(100-17)]=

900:(34:2+83)=

900:(17+83)=

900:100=

9

9+12:[42-(40-32:8)]=

9+12:[42-(40-4)]=

9+12:(42-36)=

9+12:6=

9+2=11

100×[386:2+(8×25-805:5)]=

100×[193+(200-161)=

100×(193+39)=

100×232=23200

[(2×3+45:15):9+1]:2=

[(6+3)÷9+1]:2=

(9:9+1):2=

(1+1):2=

2:2=1

[(16×3+4×5):2+3]×10=

[(48+20):2+3]×10=

(68:2+3)×10=

(34+3)×10=

37×10=370