Question

Calculeaza:
A)[1+2×(6+6÷3)-5]÷6=
B)900-[(648÷4+350÷5)÷2]×3=
C)314-2×[(16+15)-(83-79)]=
D) 324÷[108÷(21+54÷9×5÷30+45÷9)]+19=

Afla numarul necunoscut: *prin metoda mersului invers*
A.93-(85-9×9+5×8)-c=5×6+1
B.94+[(402 ÷2+5×e)×2+8]÷5=184


Va rog cat mai repede ! Dau corana!

Answer 1

a)[1+2x(6+6:3)-5]:6=
[1+2x(6+3)-5]:6
(1+2x9-5):6
(1+18-5):6
(19-5):6
14:6
2,(3) sau 2,3333333 de un infinit de ori

b) 900-[(648÷4+350÷5)÷2]×3=
900-[(162+70):2]x3
900-(232:2)x3
900-116x3
900-348
552

c) 314-2×[(16+15)-(83-79)]=
314-2x[(16+15)-(83-79)]
314-2x(31-4)
314-2x27
314-54
260

d) 324÷[108÷(21+54÷9×5÷30+45÷9)]+19=
324:[108:(21+6x5:30+5)]+19
324:[108:(21+30:30+5)]+19
324:[108:(21+1+5)]+19
324:(108:27)+19
324:4+19
81+19
100

2) .93-(85-9×9+5×8)-c=5×6+1
93-(85-81+40)-c=31
93-(4+40)-c=31
93-44-c=31
49-c=31
c=49-31
c=18

.94+[(402 ÷2+5×e)×2+8]÷5=184
94+[(201+5×e)×2+8]:5=184
94+[(201+5×e)×2+8]=184×5
94+[(201+5×e)×2+8]=920
(201+5×e)×2+8=920-94
(201+5×e)×2+8=826
(201+5×e)×2=818
201+5×e=409
5×e=208
e=208:5
e=41,6