Question

Calculeaza: a) (2/11)^6•(2/11)^4:(2/11)^3:(2/11)^5 b) [(1/2)^2]^3•[(1/4)^3]^2:(1/8)^6

Answer 1

a) (2/11)^6 x (2/11)^4 : (2/11)^3 : (2/11)^5=
(2/11)^6+4 : (2/11) ^3 : (2/11)^5 =
(2/11) ^10 : (2/11)^3 : (2/11)^5=
(2/11) ^10-3 : (2/11)^5=
(2/11)^7 : ( 2/11)^5 =
(2/11) ^7-5 =
(2/11)^2= 4/121

b) ((1/2)^2)^3 x ((1/4)^3)^2 : (1/8)^6 =
(1/2)^6 x (1/4)^6 : (1/8)^6 =
(1/2)^6 x ((1/2)^2)^6 : ((1/2)^3)^6=
(1/2)^6 x (1/2)^12 : (1/2)^18 =
(1/2)^6+12 : (1/2)^18 =
(1/2)^18 : (1/2)^18 =
(1/2)^18-18 =
(1/2)^0 =1