Question

Calculează: a) 256-[70+(70+28)]= b) (87-57)×[(376:4-2):2]= c) 2×500-[80+(247×4-801:9)-300]= d) 1 000+[(39×5+76×10):5+343]:6-300= e)[(89×100-500)×68+101]×(100-10×10)= f) [(282:3-2):2]×(500-25×4×5)=​

Answer 1

Răspuns:

a) 256-[70+(70+28) ]

= 256-(70+98)

=256-168

= 88

b) (87-57)x[(376:4-2):2]

= 30 x [(94 -2):2]

= 30 x (92:2)

= 30 x 46

= 1380

c) 2×500-[80+(247×4-801:9)-300]

=2x500-[80+(988 - 89) -300]

=2x500-(80+810-300)

=2x500-430

=1000-430

=570

d) 1 000+[(39×5+76×10):5+343]:6-300

=1000+[(195+760):5+343]:6-300

=1000+(955:5+343):6+300

=1000+(191+343):6+300

=1000+ 534:6+300

=1000+ 89+300

= 1389

e) [(89×100-500)×68+101]×(100-10×10)

=[(8900-500)x68+101]x(100-10x10)

=8850x68+101x(100-100)

=8850x68+101x0

= 0

Dacă există x0 ori cat ari fi este 0

f) [(282:3-2):2]×(500-25×4×5)=

=[(846-2):2]x(500-100x5)

=(844:2)x(500-500)

=422x0

= 0

Sper că te-am ajutat! ✮☆✯