Question

Calculează
a) 4,5+2x(3,6-0,16:0,1);
b) 0,2x[3,4-0,13:(2,9-1,6)]; c) (0,3²+0,2³):0,01+4,5:0,3; d) (5,2²-3,8²):(5,2-3,8); e) (43,5+43,5)x100-43,5x0,5; f) (3 supra 2+4 supra 5- 1 supra 10):4+0,5:0,25; g) ( 2-5 supra 4)²:3 supra 4-0,5-1 supra 4 h) (0,4²+0,(1))X1,8
Dau coroana

Answer 1

A) 4,5+2x(3,6-1,6)=4,5+2x2=4,5+4=8,5
B)0,2x(3,4-0,13:1,3)=0,2x(3,4-0,1)=0,2x3,3=0,66
C)(0,09+0,04):0,01+15=0,13:0,01+15=13+15=28
D)(27,04-14,44):(5,2-3,8)=12,6:1,4=9
E) 87x100-21,75=8700-21,75=8678,25
F)
$( \frac{3}{2} + \frac{4}{5} - \frac{1}{10} ) \div 4 + 2 = \\ \frac{5 \times 3 + 2 \times 4 - 1}{10} \div 4 + 2 =$
$\frac{15 + 8 - 1}{10} \div 4 + 2 = \\ \frac{22}{10} \times \frac{1}{4} + 2 = \frac{22}{40} + 2 =$
$\frac{22 + 40 \times 2}{40} = \frac{22 + 80}{40 } = \frac{102}{40} = 2.55$
G)
$(4 - 4 \times \frac{5}{4} + \frac{25}{16} ) \div \frac{3}{4} - \frac{5}{10} - \frac{1}{4}$
$(4 - 5 + \frac{25}{16} ) \div \frac{3}{4} - \frac{5}{10} - \frac{1}{4} = \\ \frac{16 \times 4 - 16 \times 5 + 25}{16} \times \frac{4}{3} - \frac{5}{10} - \frac{1}{4}$
$\frac{64 - 80 + 25}{16} \times \frac{4}{3} - \frac{5}{10} - \frac{1}{4} = \\ \frac{9}{16} \times \frac{4}{3} - \frac{5}{10} - \frac{1}{4} =$
$\frac{3}{4} - \frac{5}{10} - \frac{1}{4} = \\ \frac{10 \times 3 - 4 \times 5 - 10 \times 1}{40} =$
$\frac{30 - 20 - 10}{40} = \frac{0}{40} = 0$
H) (0,16+0,(1))x1,8=
$( \frac{16}{100} + \frac{1}{9}) \times \frac{18}{10} = \\ \frac{16 \times 9 +100 }{900} \times \frac{18}{10} =$
$\frac{244}{900} \times \frac{18}{10} = \frac{4392}{9000} = 0.488$