Question

calculeaza: a)6^2:3^2+3^2×3-2^1-3^0; b)[(48:2^4+7^2)-6^2]-3^2×7; c)(3^4:27+4^2:2^3):(5^2:5 .ajutatima va rog​

Answer 1

Răspuns:

$a)36 \div 9 + 9 \times 3 - 2 - 0 \\ 4 + 27 - 2 \\ 31 - 2 = 29$

b) [(48:16+49) - 36] - 63

[(3+49)-36]-63

(52-36)-63

16-63=-47

$c)(81 \div 27 + 16 \div 8) \div 5 \\ (3 + 2) \div 5 \\ 5 \div 5 = 1$