Question

calculeaza aria suprafetei totale a unui cub cu muchiile de:a=11cm,a=3intreg si 1 pe 2cm,a=2,25cm

Answer 1

$1)a = 11 \: cm$

$A_{t} = 6 {a}^{2} = 6 \times {11}^{2} = 6 \times 121 = 726 \: {cm}^{2}$

$2)a = 3 \frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{6 + 1}{2} = \frac{7}{2} = 3.5 \: cm$

$A_{t} = 6 {a}^{2} = 6 \times {3.5}^{2} = 6 \times 12.25 = 73.5 \: {cm}^{2}$

$3)a = 2.25 \: cm$

$A_{t} = 6 {a}^{2} = 6 \times {2.25}^{2} = 6 \times 5.0625 = 30.375 \: {cm}^{2}$