Question

calculează
aveti poza!

​

Answer 1

Răspuns:

$({2}^{3} \times {2}^{14} \div {2}^{15} + {3}^{18} \div {3}^{6} \div {3}^{10} + {2}^{1} + {3}^{0} ) \div {2}^{3} =$

$( {2}^{2} + {3}^{2} + 2 + 1 ) \div {2}^{3}$

$(4 + 9 + 2 + 1) \div {2}^{3}$

$(13 + 3) \div {2}^{3}$

$16 \div {2}^{3}$

$16 \div 8 = 2$

Answer 2

• Răspuns: $\red{ \boxed{ \bf 2 } }$

Explicație pas cu pas:

$\bf ( {2}^{3} \times {4}^{7} \div {8}^{5} + {27}^{6} \div {9}^{3} \div {3}^{10} + {2}^{1} + {3}^{0} ) \div {2}^{3} =$

$\bf ( {2}^{3} \times {4}^{7} \div {8}^{5} + {27}^{6} \div {9}^{3} \div {3}^{10} + 2 + 1) \div {2}^{3} =$

$\bf [ {2}^{3} \times ( {2}^{2} )^{7} \div {8}^{5} + {27}^{6} \div {9}^{3} \div {3}^{10} + 2 + 1] \div {2}^{3} =$

$\bf ( {2}^{3} \times {2}^{14} \div {8}^{5} + {27}^{6} \div {9}^{3} \div {3}^{10} + 2 + 1) \div {2}^{3}$

$\bf ( {2}^{17} \div {8}^{5} + {27}^{6} \div {9}^{3} \div {3}^{10} + 3) \div {2}^{3} =$

$\bf [ {2}^{17} \div ( {2}^{3} )^{5} + {27}^{6} \div {9}^{3} \div {3}^{10} + 3 ] \div {2}^{3} =$

$\bf ( {2}^{17} \div {2}^{15} + {27}^{6} \div {9}^{3} \div {3}^{10} + 3) \div {2}^{3} =$

$\bf ( {2}^{2} + {27}^{6} \div {9}^{3} \div {3}^{10} + 3) \div {2}^{3} =$

$\bf [ {2}^{2} + ( {3}^{3} )^{6} \div ( {3}^{2} )^{3} \div {3}^{10} + 3 ] \div {2}^{3} =$

$\bf ( {2}^{2} + {3}^{18} \div {3}^{6} \div {3}^{10} + 3) \div {2}^{3} =$

$\bf ( {2}^{2} + {3}^{12} \div {3}^{10} + 3) \div {2}^{3} =$

$\bf ( {2}^{2} + {3}^{2} + 3) \div {2}^{3} =$

$\bf (4 + 9 + 3) \div 8 = 16 \div 8 = \red{ \boxed{ \bf 2 } }$