Question

Calculeaza b=[11,2(3)-9,(2)]-1\100= ?
1\100= 1 supra 100
Ajutați ma repede ,va rog !!

Answer 1

11,2(3)=11 intregi (23-2)/90 = 11 intregi 21/90 = 1011/90
9,(2)=9 intregi 2/9 = 83/9
 
=>b=(1011/90-83/9)-1/100
    b=(1011-830)/90-1/100
    b=181/90-1/100
    b=(1810-9)/900
    b=1801/900
    b=2,00(1)