Question

Calculează: b)20•{4+10•[120+20•(36-36:4)]}
d)[(2^3)^4:(2^5)^2-17^0]•6​

Answer 1

Răspuns:

b)20•{4+10•[120+20•(36-36:4)]}=

20·{4+10·[120+20·(36-9)]}=

20·[4+10·(120+20·27)]=

20·[4+10·(120+540)]=

20·(4+10·660)=

20·(4+6600)=

20·6604=

132080

d)[(2^3)^4:(2^5)^2-17^0]•6​=

(2¹²:2¹⁰-1)·6=

(2²-1)·6=

3·6=

18

Answer 2

20 × {4 + 10 × [120 + 20 × (36 - 36 : 4)]} =

20 × [4 + 10 × (120 + 20 × 27)] =

20 × [4 + 10 × (120 + 540)] =

20 × (4 + 10 × 660) =

20 × (4+ 6600) =

20 6604 =

132080

d) [(2³)⁴ : (2⁵)² - 17⁰] × 6 = (2³×⁴ : 2⁵ײ - 1) × 6 = (2¹² : 2¹⁰ - 1) × 6 = (2² - 1) × 6 = (4 - 1) × 6 = 3 × 6 = 24