Question

Calculeaza cantitatea de glucoza de puritate 85% necesara pentru obtinerea a 10 L de etanol cu concentratia 40% si densitatea 0,94g/cm3

Answer 1

V=10L=10000cm3

ro=ms/V => ms=0,94*10000=9400g sol C2H5-OH

C=md/ms*100 => md=C*ms/100=40*9400/100 = 3760g alcool

180g................2*46g
C6H12O6 -> 2C2H5-OH + 2CO2
x=7356,52g.........3760g

p=mpur/mimpur*100 => mimpur=mp*100/p = 7356,52*100/85 = 8654,73g C6H12O6