Question

Calculeaza cantitatea de substanta si masa clorurii de hidrogen care se formeaza la interactiunea cu hidrogen a 44,8l de clor

Answer 1

H₂+Cl₂=2HCl

1mol.......................22.4 l
x moli.....................44.8 l
x=44.8*1/22.4=2moli Cl₂

1mol.........................2*35.5g Cl₂
2mol..........................y
y=2*2*35.5*/1=142g Cl₂

Masa molara HCl=1+35.5=36.5g/mol
z=masa de HCl obtinuta
z=142*2*36.5/2*35.5=146g HCl

1mol...........................36.5g HCl
w moli.........................146g HCl
w=146*1/36.5=4moli HCl