Question

Calculeaza compozitia procentuala elementala pentru urmatoarele minerale :
A. Malachit CuCO3 * Cu(OH)2 , amestec de carbonat de cupru si hidroxid de cupru
B. Calcopirita CuFeS2, sulfura de cupru si fier
C. Talc, 3 MgO * 4 SiO2 * H2O

Urgent va rog imi trebuie la toate rpd :(

Answer 1

Răspuns:

Explicație:

A.

Mmalachit= 64 + 12 + 3.16 + 64 + 2.16 + 2

                 = 124 + 98

                 =222------> 222g/moli

222g malachit-----------124 gCuCO3--------98g Cu(OH)2

100g--------------------------x--------------------------y

x=100 . 124 : 222=55,86%CuCO3

y=100 .98 : 222 =44,14% Cu(OH)2

B.

M calcopirita= 64 + 56 + 2.32

                      =184-----> 184g/moli

184g-----------------64gCu--------------56gFe-----------64gS

100g----------------------x------------------------y---------------------z

x=100.64 : 184=34,78%Cu

y=100. 56 : 184=30,44%Fe

z= 100.64: 184=34,78%S

C.

M=3.(24 + 16 ) + 4. ( 28 + 32) +18

  =120 + 240 +18

  =378

378g talc--------120g MgO---------240 g SiO2------------18g H2O

100------------------x----------------------------y---------------------z

x=100.120 : 378=31,75 % MgO

y=100.240 : 378=63,5% SiO2

z=100.18 : 378=4,76% H2O