Question

Calculează descompunand al doilea factor in suma de sute ,zeci si unități .a)3*128; 4*204;b)4*216; 2*423;c)3*274;4*198;d)2*266;5*189

Answer 1

3 × (100+20+8)=
= 300 + 60 + 24=
= 384

4 × (200+4)=
=...

4×(200+10+16)
=...

.....................................................................

Sper ca te.am ajutat!

Answer 2

a)  3x(100+20+8)=300+60+24=384
b)   4x(200+0+8)=800+32=832
c)   4x(200+10+6)=800+40+24=842
d)   2x(400+20+3)=800+40+6=846
e)   3x(200+70+4)=600+210+12=822
f)    4x(100+90+8)=400+360+32=792
g)   2x(200+60+6)=400+120+12=532
h)   5x(100+80+9)=500+400+45=945