Question

calculeaza in 2 modiri sau aplica proprietatile inmultirii
2x3+2x5
10x7+10x9
25x100+36x100
42x3-32x3
161x5-93x5
7x243-7x145

Answer 1

I mod               2 x 3 + 2 x 5 = 2 x ( 3+5)= 2 x 8 =16 
 al II -lea mod   2 x 3 + 2 x 5 = 6 +10 =16

10 x 7 + 10 x 9 = 10 x ( 7+9) = 10 x 16 =160
10 x 7 + 10 x 9 = 70 + 90 = 160 
 
25 x 100 + 36 x 100 = 100 x ( 25 + 36 ) = 100 x 61 = 6 100
25 x 100 + 36 x 100 = 2 500 + 3 600 = 6 100

42 x 3 - 32 x 3= 3 x ( 42 - 32) = 3 x 10 = 30
42 x 3 - 32 x 3 = 126 - 96 = 30 

161 x 5 - 93 x 5 = 5 x ( 161 - 93 ) = 5 x 68 = 340
161 x 5 - 93 x 5 = 805  - 465 = 340

7 x 243 - 7 x 145 = 7 x ( 243 - 145) = 7 x 98 = 686
7 x 243 - 7 x 145 = 1 701 - 1 015 =  686

Answer 2

Mod I)
2×3+2×5=6+10
=16

Mod II)
2×(3+5)=2×8
=16

_________________________

Mod I)
10×7+10×9=70+90
=160

Mod II)
10×(7+9)=10×16
=160

__________________________
Mod I)
25×100+36×100=2500+3600
=6100

Mod II)
100×(25+36)=100×61
=6100

__________________________

Mod I)
42×3-32×3=126-96
=30

Mod II)
3×(42-32)=3×10
=30

__________________________

Mod I)
161×5-93×5=805-465
=340

Mod II)
5×(161-93)=5×68
=340

___________________________

Mod I)
7×243-7×145=1701-1015
=686

Mod II)
7×(243-145)=7×98
=686