Question

Calculeaza in doua moduri:(2+3)×5=;(4+5)×8=;(9-4)×8=;(8-3)×7=;(2+1+3)×4=;(5+1+2)×7=

Answer 1

5*5=25sau2+(3*5)=2+15=17;(4+5)*8=9*8=72sau4+(5*8)=4+40=44;(9-4)*8=5*8=40sau(4*8)-9=32-9=23;(8-3)*7=5*7=35sau(3*7)-8=21-8=18;(2+1+3)*4=6*4=24sau2+1+(3*4)=3+12=15;(5+1+2)*7=8*7=56sau5+1+(2*7)=6+14=20

Answer 2

(2+3)*5=5*5=25 sau 2*5+3*5=10+15=25
(4+5)*8=9*8=72 sau 4*8+5*8=32+40=72
(9-4)*8=5*8=40 sau 9*8-4*8=72-32=40
(8-3)*7=5*7=35 sau 8*7-3*7=56-21=35
(2+1+3)*4=6*4=24 sau 2*4+1*4+3*4=8+4+12=24
(5+1+2)*7=8*7=56 sau 5*7+1*7+2*7=35+7+14=56