Question

Calculeaza in doua moduri:(2+3)×5=;(4+5)×8=;(9-4)×8=;(8-3)×7=;(2+1+3)×4=;(5+1+2)×7=;7×(6+3)=;9×(7+1)=;6×(7-4)=;5×(6-2)=;(3+2+4)×6=; (5+3+2)×8=;

Answer 1

1)  (2+3)*5=5*5=25
2)  (2+3)*5=(2*5+3*5)=10+15=25
(4+5)*8=9*8=72
(4+5)*8=(4*8+5*8)=32+40=72
(9-4)*8=5*8=40
(9-4)*8=(9*8-4*8)=72-32=40
(8-3)*7=5*7=35
(8-3)*7=8*7-3*7=56-21=35
(2+1+3)*4=6*4=24
(2+1+3*4)=(2*4+1*4+3*4)=8+4+12=24
(5+1+2)*7=8*7=56
(5+1+2)*7=(5*7+1*7+2*7)=35+7+14)=56
7*(6+3)=7*9=63
7*(6+3)=7*6+7*3)=42+21=63
9*(7+1)=9*8=72
9*(7+1)=9*7+9*1)=63+9=72
6*(7-4)=6*3=18
6*(7-4)=6*7-6*4=42-24=18
5*(6-2)=5*4=20
5*(6-2)=5*6-5*2=30-10=20
(3+2+4)*6=9*6=54
(3+2+4)*6=3*6+2* 6+4*6)=18+12+24=54
(5+3+2)*8=10*8=80
(5+3+2)*8=5*8+3*8+2*8=40+24+16+80