Calculează în două moduri: (2 + 3) x 5 = (9-4) x 8 = (4 + 5) x 8 = (8 - 3) x 7 = (2 + 1 + 3) x 4 - (5 + 1 + 2) x 7 - 7×(6 +3)= 9×(7 + 1)= 6×(7 - 4)= 5×(6 - 2)=
Răspunsuri la întrebare
Mod 1
(2 + 3) × 5 = 5 × 5 = 25
Mod 2
(2 + 3) × 5 = 2 × 5 + 3 × 5 = 10 + 15 = 25
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Mod 1
(9 - 4) × 8 = 5 × 8 = 40
Mod 2
(9 - 4) × 8 = 9 × 8 - 4 × 8 = 72 - 32 = 40
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Mod 1
(4 + 5) × 8 = 9 × 8 = 72
Mod 2
(4 + 5) × 8 = 4 × 8 + 5 × 8 = 32 + 40 = 72
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Mod 1
(8 - 3) × 7 = 5 × 7 = 35
Mod 2
(8 - 3) × 7 = 8 × 7 - 3 × 7 = 56 - 21 = 35
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Mod 1
(2 + 1 + 3) × 4 = 6 × 4 = 24
Mod 2
(2 + 1 + 3) × 4 = 2 × 4 + 1 × 4 + 3 × 4 = 8 + 4 + 12 = 24
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Mod 1
(5 + 1 + 2) × 7 = 8 × 7 = 56
Mod 2
(5 + 1 + 2) × 7 = 5 × 7 + 1 × 7 + 2 × 7 = 35 + 7 + 14 = 56
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Mod 1
7 × (6 + 3) = 7 × 9 = 63
Mod 2
7 × (6 + 3) = 7 × 6 + 7 × 3 = 42 + 21 = 63
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Mod 1
9 × (7 + 1) = 9 × 8 = 72
Mod 2
9 × (7 + 1) = 9 × 7 + 9 × 1 = 63 + 9 = 72
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Mod 1
6 × (7 - 4) = 6 × 3 = 18
Mod 2
6 × (7 - 4) = 6 × 7 - 6 × 4 = 42 - 24 = 18
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Mod 1
5 × (6 - 2) = 5 × 4 = 20
Mod 2
5 × (6 - 2) = 5 × 6 - 5 × 2 = 30 - 10 = 20
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