Question

Calculeaza in doua moduri: 4x(6+3) 6x(5-2) (9-5)x3 (8+2)x7​

Answer 1

Răspuns:

1)primul mod:

4×(6+3)=4+9=36

al doilea mod:

4×6+4×3=24+12=36

2)primul mod:

6×(5-2)=6×3=18

al doilea mod:

6×5-6×2=30-12=18

3)primul mod:

(9-5)×3=4×3=12

al doilea mod:

9×3-3×5=27-15=12

4) primul mod:

(8+2)×7=10×7=70

al doilea mod:

8×7+2×7=56+14=70

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