Question

Calculeaza in doua moduri:(6+3)×9; (9+5)×10; 8×(13-7); (16-7)×4

Answer 1

1. (6+3)x9=
    =9x9=81

 2.  6x9+3x9=
      =54+27=81

1.(9+5)x10=
    =14x10=140

2.   9x10+5x10=
      =90+50=140

1.8x(13-7)=
   =8x6=48

2. 8x13-8x7=
    =104-56=48

1.(16-7)x4=
    =9x4=36

2. 16x4-7x4=
    =64-28=36 

Answer 2

(6+3)×9= 9×9=81
(6+3)×9= 6×9 + 3×9 = 54+27=81

(9+5)×10= 14×10= 140
(9+5)×10= 9×10 + 5×10= 90+ 50= 140

8×(13-7)= 8× 6= 48
8× (13-7)= 8×13 - 8×7 = 104 - 56= 48

(16-7)×4= 9×4=36
(16-7)×4= 16×4 - 7×4 = 64- 28=36