Question

Calculează in doua moduri:(6+4)×8,(2+4)×8,(3+4)×4,.(2+6)×2,(5+4)×4,(6+3)×2,(3+5)×8,(1+5)×2.​

Answer 1

Explicație pas cu pas:

(6+4)×8=10×8

=80

(6+4)×8=6×8+4×8

=48+32

= 80

(2+4)×8= 6×8

=48

(2+4)×8= 2×8+4×8

=48

(3+4)×4= 7×4

=28

(3+4)×4=3×4+4×4

=12+16

=28

(2+6)×2=8×2

=16

(2+6)×2=2×2+6×2

=4+12

=16

(5+4)×4=9×4

=36

(5+4)×4=5×4+4×4

=20+16

=36

(6+3)×2=9×2

=18

(6+3)×2=6×2+3×2

=12+6

=18

(3+5)×8=8×8

=64

(3+5)×8=3×8+5×8

=24+40

=64

(1+5)×2=6×2

=12

(1+5)×2=1×2+2×5

=2+10

=12

Metoda aplicată se numește factorul comun