Question

Calculeaza in doua moduri:7×(6+3);9×(7+1);6×(7-4);5×(6-2); (3+2+4)×6; (5+3+2)×8

Answer 1

1. .7●6+7●3=

42+21=63

7●9=63

2.9●7+9●1

63+9=72

9●8=72

3.6●7-6●4

42-24=18

6●3=18

4.5●6-5●2

30-10=20

5●4=20

5.6●3+6●2+6●4

18+12+24=54

6●9=54.

6.8●5+8●3+8●2

40+24+16=80

8●10=80.

Sper că te-am ajutat

Answer 2

7•(6+3)=7•9=63

Al doilea mod:

7•6+7•3=42+21=63

9•(7+1)=9•8=72

Al doilea mod:

9•7+9•1=63+9=72

6•(7-4)=6•3=18

Al doilea mod:

6•7-6•4=42-24=18

5•(6-2)=5•4=20

Al doilea mod:

5•6-5•2=30-10=20

(3+2+4)•6=9•6=54

Al doilea mod:

3•6+2•6+4•6 =18+12+24=54

(5+3+2)•8=10•8=80

Al doilea mod:

5•8+3•8+2•8=40+24+16=80

SUCCES!!!!