Question

calculeaza in doua moduri:

9x(4+4)= ;
2x(5-4)= ;
6+(3+1)= ;
(7+1)x6= .

repedeeeeeeeeeeeeeeeeee!!!!!!!!!!!!!!

Answer 1

Răspuns:

9x(4+4)= 9·8=72

9·4+9·4=36+36=72

2x(5-4)=2·1=2

2·5-2·4=10-8=2

6·(3+1)= 6·4=24

6·3+6·1=18+6=24

(7+1)x6= 8·6=48

6·7+6·1=42+6=48

Answer 2

Primul mod :

9 × ( 4 + 4 ) =

9 × 8 = 72

2 × ( 5 - 4 ) =

2 × 1 = 2

6 + ( 3 + 1 ) =

6 + 4 = 10

( 7 + 1 ) × 6 =

8 × 6 = 48

Al doilea mod :

9 × ( 4 + 4 ) =

9 × 4 + 9 × 4 =

36 + 36 = 72

2 × ( 5 - 4 ) =

2 × 5 - 2 × 4 =

10 - 8 = 2

6 + ( 3 + 1 ) =

6 + 3 + 1 =

9 + 1 = 10

( 7 + 1 ) × 6 =

7 × 6 + 1 × 6 =

42 + 6 = 48