Question

Calculează in doua moduri .a)3*(2+5)= b)4*(7-2)= c)3*(2+6)= d)(7-5)*4=

Answer 1

a)
3*(2+5)= 3×7=21
3*(2+5)= 3×2+3×5=6+15=21

b)
4*(7-2)= 4×5=20
4*(7-2)=4×7-4×2=28-8=20

c)
3*(2+6)= 3×8=24
3*(2+6)= 3×2+3×6=6+18=24

d)
(7-5)*4=2×4=8
(7-5)*4=7×4-5×4=28-20=8