Question

calculeaza in doua moduri:a)3×(2+5)= ,b)5×(8-3)= ,c)9-6)×9= ​

Answer 1

a) 1. 3x(2+5)=21

2. 3x(2+5)=3x7=21

b) 1. 5x(8-3)=25

2. 5x(8-3)=5x5=25

c) 1. (9-6)x9=27

2. (9-6)x9=3x9=27

Answer 2

Modul intai calculam paranteza si apoi înmulțim
Modul doi desfacem paranteza si apoi calculam separat
a) Modul intai : 3•(2+5)=3•7=21
Modul doi :3•(2+5)=3•2+3•5=6+15=21
b) Modul intai :5•(8-3)=5•5=25
Modul doi :5•(8-3)=5•8-5•3=40-15=25
c) Modul intai :(9-6)•9=3•9=27
Modul doi :(9-6)•9=9•9-9•6=81-54=27

Sper ca te-am ajutat!