Question

calculeaza in doua moduri :a)7×(21+16)=?,(136+13)×4=?,(130-18)×2=?,4×(425-350)=?,(34+16)×17=?,12×(52-25)=?,17×(94-39)=?​

Answer 1

Răspuns:

7x(21+16)=7x37=259

   sau:        =7x21+7x16=147+112=259

(136+13)x4=149x4=596

    sau:            =136x4+13x4=544+52=596

(130-18)x2=112x2=224

     sau:          =130x2-18x2=260-36=224

4x(425-350)=4x75=300

sau :    4x425-4x350=1700-1400=300

(34+16)x17=50x17=850

sau:  34x17+16x17=578+272=850

12x(52-25)=12x27=324

sau: 12x52-12x25=624-300=324

17x(94-39)=17x55=935

sau: 17x94-17x39=1598- 663=935

Answer 2

7×(21+16)=7×37=259 primul mod

7×(21+16)=7×21+7×16=147+112=259 al doilea mod

(136+13)×4=149×4=596 primul mod

(136+13)×4=136×4+13×4=544+52 al doilea mod

(130-18)×2=112×2=224 primul mod

(130-18)×2=130×2-18×2=260-36=224 al doilea mod

4×(425-350)=4×75=300 primul mod

4×(425-350)=4×425-4×350=1700-1400=300 al doilea mod

(34+16)×17=50×17=850 primul mod

(34+16)×17=34×17+16×17=578+272=850

al doilea mod

12×(52-25)=12×27=324 primul mod

12×(52-25)= 12×52-12×25=624-300=324 al doilea mod

17×(94-39)=17×55=835 primul mod

17×(94-39)=17×94-17×39=1598-663=835 al doilea mod