Question

Calculeaza in doua moduri,dupa modelul de rezolvare dat

(45+36)x3=45x3+36x3=135+108=243
(45+36)x3=81x3=243

a.(39+27)x5
(64+84)x3

b.(143+257)x4
(974-361)x4

c.(2483+3156)x4
(5615-2184)x3

Answer 1

a.
(39+27)•5=39•5+27•5=195+135=330
(39+27)•5= 66•5=330

(64+84)•3=64•3+84•3=192+252=444
(64+84)•3=148•3=444

b. (143+257)•4=143•4+257•4=572+1028=1600
(143+257)•4=400•4=1600

(974-361)•4=974•4-361•4=3896-1444=2452
(974-361)•4=613•4=2452

c.(2483+3156)•4=2483•4+3156•4=9932+12624=22556
(2483+3156)•4=5639•4=22556

(5615-2184)•3=5615•3-2184•3=16845-6552=10293
(5615-2184)•3=3431•3=10293

Answer 2

a) ( 39+27) x 5=39 x 5 +27 x 5=195+135=330

   ( 39+27) x 5 =66 x 5=330

   

(64+84) x 3 =64 x 3+ 84 x 3=192+252=444

( 64+84 ) x 3=148 x 3=444

b) (143+257) x 4=143 x 4+ 257 x 4=572+1028=1600

( 143+257) x 4=400 x 4 =1600

( 974-361) x 4=974 x 4-361 x 4=3896-1444=2452

( 974-361) x 4=613 x 4=2452

 

c) ( 2483 +3156) x 4=2483 x 4+3156 x 4=9932+12624=22556

 (2483+3156) x 4=5639 x 4=22556

( 5615-2184) x 3=5615 x 3 - 2184 x 3=16845-6552=10293

( 5615-2184) x 3=3431 x 3=10293