Question

Calculeaza masa alcoolului etilic si volumul dioxidului de carbon care se formeaza la fermentatia alcoolica a glucozei C6H12OH cu masa de 18g.

Answer 1

180g..................92g......................88g
C6H12O6 --> 2CH3-CH2-OH + 2CO2
18g...................x=9,2g................y=8.8g

n=m/M=8.8/44=0.2 moli CO2

n=V/Vmolar==>V=n*Vmolar=0.2*22.4=4.48 L CO2

MC6H12O6=180g/mol
MCO2=44g/mol
MCH3-CH2-OH=46g/mol