Question

calculeaza masa de acid sulfuric dizolvat in 500 ml solutie de concentratie 20% si densitate de 1,143 g/ml

Answer 1

$\int\limits= \frac{m}{v} = \frac{kg}{l} =\frac{q}{ml} = \int\limits*v \\ V=500ml \\ c=20 \\ ms=1,143*500=571,5g \\ \frac{md*100}{ms} = \frac{md*100}{571,5} =20 \\ md=(20*571,5):100=11430:100=114,3g$