Question

Calculeaza masa de clorura de sodiu care se formeaza in urma reactiei dintre 23 g NaHCO3 si 13,5 HCl , in soluie apoasa 

Answer 1

84            36.5  58.5
NaHCO3+HCl=  NaCl+H2O+CO2
23            13.5    x

M NaHCO3=23+1+12+16*3=84
M HCl=1+35.5=36.5
M NaCl=23+35.5=58.5
x=13.5*58.5/36.5
x=789.75/36.5
x=21.63 grame

Answer 2

NaHCO3 + HCl ---> NaCl + H2O + CO2
84 g NaHCO3 ..........58,5 g NaCl
23 g NaHCO3.............x g NaCl
x = 21,637 g NaCl