Question

calculeaza masa hidrogenului de calciu obtinut prin stingerea cu
apa a oxidului de calciu cu masa de 112kg. Ce masa si ce volum de apa se consuma in reactie

Answer 1

Se da:
m(Ca)=112Kg=112000g
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m(H2O)-?
V(H2O)-?
m(Ca(OH)2)-?


sriem ecuatiea

CaO+H2O=Ca(OH)2

niu=m/M
niu=V/V(molar)

niu(CaO)=m(CaO)/M(CaO)=112000g / 56g/mol =2000 mol

DUPA COIFICIENTI

niu(CaO)=niu(Ca(OH)2)=2000mol

niu(Ca(OH)2)=m(Ca(OH)2) / M(Ca(OH)2)
m(Ca(OH)2)=M(Ca(OH)2)*niu(Ca(OH)2)
m(Ca(OH)2)=74g/mol * 2000 mol =148000 g

niu(H20)=niu(Ca(OH)2)
niu(H20)=m(H20)/M(H20)
m(H20)=niu(H20)*M(H20)=2000*18=36000g

niu(H20)=V(H20)/Vmol
V(H20)=niu(H20)*Vmol=2000 * 22,4=44800 l

raspuns:  V(H20)=44800 l ;m(H20)=36000g;m(Ca(OH)2)=148000 g